The M1919A6, has the same muzzle velocity and calibre as the M1903 below…
Using the calculation of F=ma, we can see that, 26.9g at 830 m/sec produces 5 lbs of force for the springfield, if we divide the hit power by the force we get 4.42 hit power per lb of force.
Whereas if we do the same calculation with the M1919A6, we get 4.8 lbs of force, due to the slightly lighter cartridge mass of 25.9, however when we divide this by the hit power of 12, we get 2.5 hit power per lb of force.
That makes absolutely no sense. Why should two weapons with the same muzzle velocity and ammunition type, create vastly different hit powers? Even with the slight deviation in cartridge mass, we can see there is a massive discrepancy.
exactly - so it makes me wonder why even both putting in cartridge mass details and muzzle velocities, if they have absolutely no bearing on the game whatsoever.
Huh? the question makes no sense - if there’s a mistake in the figures then of course there’s a mistake in the calculated result, but that is irrelevant to actual reality.
the bullets and cartridge’s are the same - with either identical muzzle velocities or if not then very close ones due to different barrel lengths.
There is no physics that allows them to behave differently.
But we dont know the mass of the projectile inside the cartridge.
I mean - even if we ignore differences in mechanism of these two firearms (machine gun vs bolt action crap), then for example - Browning can use a lighter bullets and more of a bad quality gun-powder.
The same cartridge mass, the same muzzle velocity, but - lighter bullets and less energy ?
Energy of the bullet depends on two factors - its mass and its speed. If both guns shoots bullets at the same speed and one gun does smaller damage then one gun must use lighter bullets.
They are probably the same and that is what I thought, that the smaller damage is a result of different mechanism of the guns. But the screens state clearly the same speed of the bullets (830 m/s) so I was curious about this.